The area is 1.3 acres when you round to the correct number of significant figures. The unrounded value is about 1.3222 acres, and the limiting measurement is the 120-yard length, which carries either two significant figures (120) or three (120.) depending on how it's written — this ambiguity is exactly what trips people up, and it's why the defensible classroom answer is 1.3 acres, with 1.32 acres acceptable if you treat 120 as having three significant figures.

That one-paragraph answer won't satisfy a chemistry lab report, though. You need the full chain: yards to feet, feet squared to acres, and a sig-fig decision at the end. What follows walks the arithmetic line by line, then goes after the part most answer keys skip — why the same problem produces 1.3, 1.32, and even 1 acre depending on how the width is written.

The Exact Arithmetic Chain From 120 by 53.333 Yards to Acres

Start with the area in square yards: 120 × 53.333 = 6,399.96 yd². That number isn't an accident. A regulation American football field is 360 feet long including both 10-yard end zones and 160 feet wide, which works out to 57,600 ft² exactly — and 57,600 ÷ 9 = 6,400 yd². The 53.333 figure is the decimal form of 53⅓, the true field width in yards.

Convert square yards to square feet by multiplying by 9, since one square yard is 3 feet by 3 feet. That gives 6,399.96 × 9 = 57,599.64 ft². If you instead convert each dimension first — 120 yd = 360 ft and 53.333 yd = 159.999 ft — you get 360 × 159.999 = 57,599.64 ft². Same number, different road.

Now divide by the acre definition: 57,599.64 ÷ 43,560 = 1.32222... acres. The repeating decimal is the honest answer before rounding, and it's worth writing down before you touch a rounding rule, because sig figs are applied once, at the end, never mid-calculation.

Notice how close that lands to a clean 1.32. The tiny gap between 57,599.64 and the exact 57,600 comes entirely from writing 53⅓ as 53.333. Had the problem used 53.3333 with more threes, the result would sit even closer to 1.32231 acres. That drift is a rounding artifact, not a real difference in field size.

Why the Answer Is 1.3 Acres Under Strict Sig-Fig Rules

Multiplication and division rules say the result carries the same number of significant figures as the measurement with the fewest. The width, 53.333, has five. The length, 120, is the problem child: written without a decimal point or overbar, trailing zeros in a whole number are ambiguous, and most textbooks treat it as two significant figures.

Two significant figures applied to 1.32222 gives 1.3 acres. That's the answer a strict grader wants, and it's the one that shows you understood the limiting-term concept rather than just copying a calculator display.

Some instructors read 120 as three significant figures, reasoning that the measurement was recorded to the nearest yard. Under that reading the answer becomes 1.32 acres. Both appear in published solution keys, which is why students comparing notes get confused — the discrepancy lives in the interpretation of the input, not in the math.

Here's the decision laid out plainly:

Sig figs assigned to 120 Limiting term Rounded area Typical context
2 (bare "120") 120 1.3 acres Strict textbook grading
3 ("120." with decimal) 120. 1.32 acres Lab reports, instructor preference
1 (sloppy reading) 120 1 acre Wrong — trailing zeros aren't automatically insignificant

Write your reasoning next to the answer. A grader who sees "120 has two sig figs, so the result rounds to 1.3 acres" can follow your logic even if their key says 1.32, and most will credit it.

The 1 Acre Trap: When Rounding to One Significant Figure Goes Wrong

Some students glance at a bare 120, decide it has one significant figure, and round 1.32222 all the way down to 1 acre. That's a misreading of the rules, and it's worth understanding why so you don't fall into it. Trailing zeros in a whole number without a decimal point are ambiguous — they're never automatically insignificant.

The convention in most chemistry texts, including the significant-figures chapters in standard general-chemistry curricula, is that 120 sits at two significant figures unless marked otherwise. A decimal point (120.) or an overbar on the zero pins it at three. Nothing pins it at one.

The practical damage shows up in lab work. If you report 1 acre for a field that's genuinely 1.32 acres, you've thrown away 24% of the measured value. Sig figs are supposed to communicate measurement precision, not erase real information — and the precision of the length measurement was never that poor.

There's also a units trap hiding in the same problem. A few published solutions convert yards directly to acres using 1 yard = 0.000206612 acres and get tangled, because that factor applies to linear yards, not square yards. The clean path is always area-to-area: square yards to square feet to acres, or square yards straight to acres using 1 acre = 4,840 yd².

Square Yards to Acres Direct: The 4,840 Shortcut That Skips Feet Entirely

You don't have to pass through square feet at all. One acre equals 4,840 square yards — that's 43,560 ft² ÷ 9 — so 6,399.96 ÷ 4,840 = 1.32231 acres. The two routes agree to four decimal places, which makes this a useful self-check in an exam setting.

The shortcut earns its keep when a problem gives dimensions in yards and asks for acres. Fewer conversion steps means fewer places to drop a factor of 3. It also sidesteps the most common error in this problem type: converting one dimension to feet and forgetting the other.

Use the ft² route when the problem hands you 43,560 explicitly, as this one does. Use the 4,840 route when you want a fast sanity check. Doing both takes fifteen seconds and catches arithmetic slips before they reach your final answer.

One caveat: the shortcut only works because both figures describe the same acre. The international acre and the US survey acre differ by about 4 parts per million — 4,046.8564224 m² versus 4,046.87261 m² — a distinction that matters in land surveying but never in a general chemistry problem. If your course uses 43,560 ft², you're working with the international acre.

Reading 53.333 Correctly: Five Sig Figs, Not Six

The width 53.333 contains five significant figures: the digits 5, 3, 3, 3, 3. Every one counts because they sit between the decimal point and the end of the number, and trailing digits after a decimal are always significant.

That matters because students sometimes miscount it as six or shrug and call it "a lot." The precise count determines nothing here — 120 is the limiting term either way — but writing "five sig figs" in your work shows the grader you applied the rule deliberately rather than guessing.

The number itself is a rounded form of 53⅓, the exact width of a regulation field measured in yards (160 feet ÷ 3). Because ⅓ doesn't terminate in decimal, any written version is an approximation, and the more threes you include, the closer the computed area creeps toward the exact 57,600 ft².

Here's the sensitivity, computed directly: with 53.333 the area is 57,599.64 ft²; with 53.3333 it's 57,599.96 ft²; with the exact fraction it's 57,600 ft². All three round to 1.32 acres at three sig figs and 1.3 at two. The width's precision never changes the graded answer — only the length's does.

A Worked Lab-Report Version You Can Copy Line by Line

Lab notebooks want a chain of equalities with units canceling, not a paragraph. Set it up like this, and the sig-fig decision becomes the last visible step rather than an afterthought.

1: Area in square yards: 120 yd × 53.333 yd = 6,399.96 yd² (carry extra digits; don't round yet). 2: Convert to square feet: 6,399.96 yd² × 9 ft²/yd² = 57,599.64 ft². 3: Convert to acres: 57,599.64 ft² ÷ 43,560 ft²/acre = 1.32222 acres. 4: Identify the limiting term: 120 yd carries two significant figures; 53.333 carries five. 5: Round once, at the end: 1.32222 → 1.3 acres (two significant figures).

If your instructor treats 120 as three sig figs, step 5 becomes 1.32 acres. State your assumption in the report — "treating 120 yd as two significant figures" — and the grader can see the decision was deliberate.

Failure handling: if your two conversion routes disagree (say 1.32 from the ft² path and 1.30 from the yd² path), you've almost certainly dropped a factor of 9 somewhere. Recheck step 2 first; it's the step where square-unit conversions most often go wrong.

Significant Figures for Multiplication and Division: The Rule Behind the Rounding

The rule is short: for multiplication and division, count sig figs in each input, find the smallest count, and give the result that many. Addition and subtraction work differently — they track decimal places — which is why mixing the two rule sets in one problem causes errors.

Apply it here. Length: 120 → two sig figs under the standard reading. Width: 53.333 → five. Conversion factors (9 ft²/yd² and 43,560 ft²/acre) are exact definitions, so they impose no limit. The smallest count is two, so the answer carries two: 1.3 acres.

Exact conversion factors are the part students underuse. A factor derived from a definition — 3 feet per yard, 43,560 square feet per acre — has infinite precision and never limits your answer. Only the measured field dimensions do.

One more subtlety: apply the rule to the final result only. Rounding 6,399.96 to 6,400 mid-problem and then converting introduces small errors that compound. Keep full precision on the calculator and round once.

Common Mistakes That Turn 1.32 Acres Into 1 Acre or 11.9 Acres

The errors cluster around three habits, and each produces a recognizably wrong answer you can diagnose instantly.

Forgetting to square the conversion factor. Converting 6,400 yd² by multiplying by 3 instead of 9 gives 19,200 ft², which divides to 0.44 acres — less than half a field, obviously absurd to anyone who's stood on one. Square units scale by the square of the linear factor, always.

Rounding mid-calculation. Truncating 53.333 to 53 before multiplying gives 6,360 yd² and 1.314 acres, close enough to look right but wrong in the third digit. Sig figs are a reporting convention, not an arithmetic shortcut.

Inverting the acre conversion. Dividing 43,560 by 57,600 instead of the reverse yields 0.756 — a plausible-looking number that fails a basic check, since any football field visibly occupies more than three-quarters of an acre.

A sanity anchor helps: an acre is 43,560 ft², and a football field is 57,600 ft². The field must therefore be bigger than one acre, and 57,600 ÷ 43,560 ≈ 1.32 confirms it. If your answer comes out below 1, you've inverted something.

FAQ

Is a football field exactly 1 acre?

No — it's about 1.32 acres, roughly a third larger than one acre. The field measures 57,600 ft² against an acre's 43,560 ft², and that ratio of 1.3223 is fixed by the dimensions, not by measurement precision. Only the reported sig figs change how you write it.

Why do some answer keys say 1.3 acres and others say 1.32?

The split comes from how each key reads the number 120. Treating it as two significant figures yields 1.3; treating it as three yields 1.32. The underlying area is identical — the disagreement is purely about the precision assigned to the length input. Check which convention your course uses before submitting.

Does the answer change if I use 53.33 instead of 53.333?

Barely. At 53.33 the area computes to 57,596.4 ft², or 1.32214 acres — still 1.32 at three sig figs and 1.3 at two. The width's trailing digits shift the fourth decimal place, never the graded digit, because the length is the limiting measurement.

How many square yards are in an acre?

Exactly 4,840 square yards, since 43,560 ft² ÷ 9 ft²/yd² = 4,840. That's why the shortcut 6,400 ÷ 4,840 = 1.3223 acres works without ever converting to feet. Keep the figure handy for any yards-based area problem.

What if the problem writes the length as 120. with a decimal point?

Then 120. carries three significant figures, and the answer becomes 1.32 acres. The decimal point is the standard notation for pinning trailing zeros as significant. Without it, the conservative reading is two sig figs and 1.3 acres.

Is the end zone included in the 120 yards?

Yes. The 120-yard figure spans goal line to goal line (100 yards) plus both 10-yard end zones. The playing field between the goal lines alone is 100 × 53⅓ yards, about 1.1 acres — a different number entirely, so confirm which measurement a problem intends.

Why is the field 53⅓ yards wide rather than a round number?

The width descends from 160 feet, a round figure in the imperial system the sport grew up in. Expressed in yards, 160 ÷ 3 = 53⅓, which forces the repeating decimal. That's why problems hand you 53.333 — it's a courtesy conversion of an exact fraction, not a measured value.